Sensory Systems · Unit 6: Hearing and balance
The Cochlear Amplifier and Otoacoustic Emissions
The core course showed that outer hair cells need prestin to amplify sound. This lesson asks how the motor works, whether the hair bundle is a second engine, why a healthy ear sends sound back out, and where inside the living cochlea the gain is built. Afterwards you can read a nonlinear-capacitance curve, say what a structure of a ligand-bound protein can and cannot show, and interpret in vivo motion measurements and an otoacoustic emission test.
Watch first What the returning sound leaves out · 2:58
A microphone sealed in a healthy ear canal can record sound that the cochlea made. What does that returning sound tell us about the amplifier, and what does it leave out?
The core lesson hearing and balance established that outer hair cells shorten and lengthen with voltage, that the protein prestin is the motor, and that a knock-in mouse supports a requirement for its motility. This lesson starts after that point. It asks how the motor works, whether the hair bundle is a second engine, what sound the ear emits, and where inside the living cochlea the gain is built. Each answer comes from a different preparation, and none of them is complete.
What a motor must do, and what the structures show
A tone at 20 kHz, near the top of the human range, completes a cycle every 50 microseconds. An amplifier that adds energy on every cycle cannot wait for a chemical step each time, so the outer hair cell uses a protein that responds to voltage directly. Prestin belongs to the SLC26 family of anion transporters (membrane transport), yet in the outer hair cell it works as a motor.
Three structural papers appeared within about a year, each on a different species and with a different emphasis:
- Ge and colleagues (Cell, 2021) solved full-length human prestin, expressed in HEK293 GnTI-minus cells and purified into detergent micelles or lipid nanodiscs. It is a domain-swapped homodimer. The dimers solved in chloride and in salicylate differ by about 200 square angstroms (2 square nanometres) in mean transmembrane cross-sectional area, and an ordered ring of lipid surrounds the protein. The authors proposed that a shape change of the protein is coupled to a change in membrane area.
- Bavi and colleagues (Nature, 2021) resolved recombinant dolphin prestin in six distinct states. They suggested that the voltage sensor is a composite of a bound anion, coordinating charged residues and a helix dipole, and interpreted salicylate inhibition as the protein being held in one conformation.
- Butan and colleagues (Nature Communications, 2022) solved gerbil prestin at 3.6 angstroms. Each protomer has 14 transmembrane helices, and the cytoplasmic STAS domains are swapped. The anion-site mutant S398E kept its nonlinear capacitance in 20 millimolar salicylate, which the authors argued is hard to reconcile with a chloride-only extrinsic voltage sensor.
A later study combined molecular dynamics of human prestin with fluorescence and functional tests on rat prestin constructs (in cultured CHO cells and Xenopus oocytes) and supported an elevator-like movement of a transport domain, while stating that chloride’s role was still unclear (Kuwabara and colleagues, Nature Communications, 2023).
Read these as complementary views, not one settled movie. Every structure is of purified protein held in a state by a ligand. Butan and colleagues cautioned that salicylate- or sulfate-stabilized structures could differ from the shapes of a voltage-driven protein. The 200 square angstrom figure compares two structures. It is not a stroke measured in a hair cell, and it is not mechanical work.
Reading a nonlinear-capacitance curve
How do you connect a structure to an electrical response? One answer is nonlinear capacitance (NLC). In whole-cell voltage clamp a cell expressing prestin shows a bell-shaped capacitance that peaks at one voltage. The usual reading is that NLC reports voltage-dependent displacement of charge in the protein. Depolarization shifts prestin toward a contracted state, the state associated with outer hair cell shortening.
A minimal model has two states. With occupancy f of the contracted state, an effective valence z and a half-activation voltage Vh:
f(V) = 1 / (1 + exp(-z (V - Vh) / (kT/e))), normalized NLC = 4 f (1 - f)
Worked problem. Butan and colleagues fitted gerbil prestin in an induced HEK cell line with Vh = -112 mV and z = 0.70 (an effective charge, not a count of transported chloride ions). Assume 295 K, a two-state equilibrium, no linear capacitance and no kinetics, so kT/e = 25.42 mV. What are the occupancy and normalized NLC at Vh and at -62 mV?
Step 1: at Vh. The exponent is zero, so f = 0.5 and normalized NLC = 4 x 0.5 x 0.5 = 1, the peak.
Step 2: at -62 mV. The shift is -62 - (-112) = +50 mV. The exponent is -0.70 x 50 / 25.42 = -1.377, so f = 1 / (1 + 0.2523) = 0.798. Occupancy rose by 0.298.
Step 3: capacitance. Normalized NLC = 4 x 0.798 x 0.202 = 0.644, about 64 percent of the peak.
Step 4: check. At -162 mV, 50 mV hyperpolarized from Vh, f = 0.202 and NLC is again 0.644.
This is charge movement in a cell line at room temperature, under stated assumptions. It says how the protein’s charge responds to voltage. It does not say how much force or power a hair cell produces. The Butan result also shows why controls matter: before reading drug insensitivity of NLC, you need expression, localization and baseline NLC for each mutant.
Hollow orange circles mark the mirror voltage, the same distance on the other side of Vh.
- V − Vh
- +50 mV
- Exponent −z(V − Vh)/(kT/e)
- −1.377
- Occupancy f (contracted)
- 0.798
- Change in f from Vh (0.5)
- +0.298
- NLC as a fraction of peak
- 0.644
In this sketch: two-state equilibrium, no linear capacitance, no kinetics, kT/e = 25.42 mV (295 K). Vh = −112 mV and z = 0.70 are the values fitted to gerbil prestin in an induced HEK cell line at room temperature (Butan and colleagues, 2022). The curves are computed from the lesson’s equation, not recorded.
Keep this rule: the bell reports how the protein’s charge responds to voltage in a cell line. It does not say how much force or power a hair cell produces.
A second engine, measured in a frog
Outer hair cell bodies are not the only candidate. Martin and Hudspeth (PNAS, 1999) used adult bullfrog saccular epithelium in vitro, with the otolithic membrane removed. A two-compartment chamber let the apical side bathe in artificial endolymph. A flexible probe moved single bundles while photometry tracked them. Some bundles oscillated spontaneously, up to 50 nanometres, at 5 to 40 Hz.
Why does a work balance matter more than a large movement? A passive bundle pushed by a probe can move far, because the probe supplies the energy. The authors found that the bundle dissipated more energy through viscous drag than the probe supplied, so the bundle itself added energy.
Mammals are different cells in a different organ. In his review (Nature Reviews Neuroscience, 2014), Hudspeth states that in mammals bundle motility operates in conjunction with prestin-based somatic motility, and that both bundles and the whole cochlea operate near a dynamical instability, the Hopf bifurcation. The frog experiment gives no mammalian number for how the work is split between the two, and no split has been established. The current that drives both engines is the subject of the hair-cell transduction channel.
Sound coming back out
Kemp (J. Acoust. Soc. Am., 1978) studied human ears in vivo. Brief acoustic impulses were delivered to the closed ear canal and the canal response was signal-averaged. Beyond 5 milliseconds after the stimulus, a slowly decaying component remained, with a decay constant over 12 ms. In the ears with cochlear deafness that were tested, it was absent. That supports a cochlear source. It does not identify a motor.
A second kind of emission uses two tones. If f1 and f2 are played together, a nonlinear cochlea also produces energy at 2f1 - f2; Boero and colleagues recorded this distortion product in mice. Suppose f1 = 2,000 Hz and f2 = 2,400 Hz in an invented example: 2 x 2,000 - 2,400 = 1,600 Hz, a frequency the stimulus did not contain.
Emission tests are used in newborn hearing screening. A pass shows that outer hair cell activity can produce an emission through the middle ear. It does not show intact hearing, because auditory neuropathy can present with a normal emission and an absent or very abnormal auditory brainstem response (NIDCD). Emission and brainstem tests probe different stages.
The outer hair cell also receives input from the brain. Medial olivocochlear efferents release acetylcholine, which acts through nicotinic receptors containing the alpha-9 and alpha-10 subunits. Calcium entry activates nearby calcium-dependent potassium channels, and acetylcholine suppresses outer hair cell electromotility by shunting and hyperpolarization (reviewed by Fuchs and Lauer, 2019). In mice, Boero and colleagues (2018) exposed animals at postnatal day 21 to 1 to 16 kHz noise at 100 dB SPL for one hour. Wild-type mice recovered thresholds but lost ribbon synapses. Mice lacking Chrna9 kept permanent threshold elevations, and mice with a gain-of-function receptor (L9’T) resisted the same protocol. That is conditional protection in constitutive mouse genotypes at one age and one exposure, not a treatment and not evidence about people.
Inside the living cochlea: where gain accumulates
Older measurements of the basilar membrane gave one number at one place. Newer optical methods look at several depths in the living organ of Corti. Three mouse studies are worth comparing.
- Ren, He and Kemp (PNAS, 2016) used anaesthetized CBA/CaJ mice aged 3 to 5 weeks, at a basal site about 0.85 mm from the base. Reticular-lamina motion exceeded basilar-membrane motion at lower frequencies and near the best frequency at 20 to 50 dB SPL, but not significantly at 60 to 80 dB SPL. The magnitude and phase differences disappeared postmortem.
- Lee and colleagues (J. Neurosci., 2016) imaged the apex through the intact otic capsule in mice aged P28 to P42, with tones from 2 to 13 kHz. Radial tuning persisted postmortem, which they took to suggest a passive contribution within the organ of Corti.
- Dewey, Applegate and Oghalai (J. Neurosci., 2019) used 4 to 6 week old CBA/CaJ mice and a site whose best frequency was about 9 to 9.5 kHz, with two-tone suppression. They concluded that forces from outer hair cells accumulate mainly near the peak of the travelling wave.
These studies used different sites, different questions and different readouts, so they do not simply contradict or confirm one another. The unsettled point is how far along the cochlea gain is built, and how much is local.
Design problem
Two groups measure motion inside the living cochlea. One favours gain that accumulates along the cochlea; the other favours gain made locally. Design an experiment to separate them, then interpret this result: in a living mouse, reticular-lamina motion exceeds basilar-membrane motion at and below the best frequency, and the difference disappears postmortem.
One way to do it
Measure motion at matched sites with depth and direction resolved, so the reticular lamina and the basilar membrane are read in the same radial segment. Probe near the best frequency, then add a second suppressing tone with its frequency place basal to the measurement site. If gain accumulates from distant regions, suppressors there should reduce the local response. If gain is made locally, only suppressors near the site should matter. Repeat each condition postmortem in the same animal as a control.
Dewey and colleagues made the suppression measurements in living mice at an apical site with a 60 dB SPL probe near the best frequency; they did not repeat them after death, so the postmortem control is an extension proposed here. They estimated buildup distances of 0.95 +/- 0.024 mm (mean +/- SEM, n = 8) for the basilar membrane and 0.71 +/- 0.042 mm (n = 10) for the reticular lamina. That points to a limited stretch of cochlea contributing, not the whole base.
For the stated result: a difference that vanishes after death depends on the living state, and larger reticular-lamina motion shows the organ of Corti is not moving as one block. The result does not show where the energy comes from or how it is split between bundles and cell bodies. Motion is not work done. One apical site in one strain at one level is not a map of the cochlea, and the basal site of Ren and the apical site of Dewey cannot be assumed to behave alike.
How we measure it
Single-particle cryo-EM
Purified protein is frozen in a thin film and imaged, and many particle images are averaged into a three-dimensional map. It shows the architecture and ligand-associated states of the protein, but it does not measure force, work or voltage-driven movement.
Whole-cell voltage clamp with nonlinear-capacitance analysis
The voltage of a cell is stepped or ramped while capacitance is measured. A bell-shaped capacitance peak reports voltage-dependent displacement of charge, and a two-state Boltzmann fit gives a half-activation voltage and an effective charge.
Optical coherence vibrometry with two-tone suppression
Light reflected from several depths of the living cochlea gives motion of the basilar membrane and the reticular lamina at once. A second, suppressing tone then tests which regions of the cochlea set the gain at the measured site.
Ear-canal acoustic recording with signal averaging
A microphone in the sealed ear canal records the response to clicks or to two pure tones, and averaging separates the faint cochlear emission from noise. It tests outer hair cell function without entering the ear.
Finish line
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Practice and MCAT-style, with explained answers.
Next · Lesson 24
Hidden Hearing Loss, Gene Therapy and Regeneration
A mouse can pass its hearing test after loud noise and still have lost about half the ribbon synapses at one place in the cochlea. What does a normal threshold actually tell you?
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