Neuroscience · Unit 3: Sensory systems

Hearing and Balance

How does a bundle of stiff hairs turn a vibration far smaller than a cell into a current, and how does the brain use that current to tell pitch, place and head motion apart? This lesson follows the hair cell from force to transmitter, the cochlea as a frequency map with an amplifier, the brainstem circuits that compare the two ears, and the canals and otoliths that steady the eyes. Afterwards you can place a frequency on the cochlea, compute an interaural time difference, and trace the horizontal vestibulo-ocular reflex.

Watch first Pitch Becomes a Place Along the Cochlea · 2:42

One kind of cell, the hair cell, tells you that a violin is playing an A, that the violin is to your left, and that your head has just turned toward it.

The inner ear has two parts that share this cell. The cochlea, a coiled tube, analyses sound. The vestibular organs, three semicircular canals and two otolith organs, sense head motion and gravity. In both, a hair cell turns a tiny movement into a graded voltage; what differs is the mechanics around the cell and the circuits that read it. Sensory coding covers transduction and receptive fields in general.

The hair bundle: force to current

On top of each hair cell sits a hair bundle, rows of stiff stereocilia graded in height like a staircase. Many vestibular hair cells also have a true cilium, the kinocilium, beside the tallest row; mammalian cochlear hair cells lose it as they mature. Fine tip links run from the tip of each stereocilium to its taller neighbour. Each link is made of cadherin 23 and protocadherin 15, whose ends overlap in a handshake (Sotomayor and colleagues, 2012, crystal structures).

Push the bundle toward its tallest stereocilia and the tip links tighten and pull open mechanically gated cation channels. Calcium imaging in neonatal rat cochlear hair cells implies that the working channels sit at the lower end of each link (Beurg and colleagues, 2009). Push the other way and the links slacken, the channels that were open at rest close, and the cell hyperpolarizes. The gating machinery belongs to ion channels as receptors; in short, mutating a protein called TMC1 in mouse hair cells changed how ions pass, making TMC1 part of the pore (Pan and colleagues, 2018), though the full native complex is not solved.

Hudspeth and Corey (1977) measured this relation in hair cells of the bullfrog sacculus in vitro, recording intracellularly while moving single bundles. Deflection toward the kinocilium gave the depolarizing response. Voltages were graded, up to about 15 mV, with a peak slope near 20 mV per micrometre. Those numbers belong to that frog preparation, not to the human cochlea.

What carries the current? The top of the hair cell faces endolymph, a fluid rich in K+ that, in the cochlea, is held positive (by roughly +80 mV in mammals) by the endocochlear potential (vestibular endolymph is only slightly positive); making it is a transport problem (membrane transport). The driving force on an ion is the membrane potential minus that ion’s equilibrium potential (the resting membrane). In round illustrative numbers, suppose the cell sits at −50 mV and the endolymph at +80 mV, with K+ about equally concentrated on both sides of the top membrane. Equal concentrations mean K+ would be at equilibrium only with no voltage across that membrane, so the whole 130 mV pushes K+ inward. Opening channels lets K+ in, and the cell depolarizes, the reverse of most neurons, where K+ leaves.

The depolarization opens voltage-gated Ca2+ channels at the base. Mouse inner hair cells lacking the L-type channel CaV1.3 showed only marginal depolarization-evoked exocytosis (Brandt, Striessnig and Moser, 2003), so Ca2+ entry drives release, as at other synapses (synaptic transmission). The release site is a ribbon synapse. Mature mammalian cochlear hair cells, once lost, are not replaced (injury and regeneration).

The cochlea as a frequency map, and its amplifier

Cochlear hair cells sit on the basilar membrane, which runs the length of the coil. Near the base, where sound enters, the membrane is narrow and stiff; toward the apex it is wider and more compliant. Sound sets up a travelling wave that moves from base to apex, grows until it reaches the place whose stiffness suits its frequency, peaks, and dies away. High frequencies peak near the base, low frequencies near the apex. This map of frequency onto position is tonotopy, and it is kept at every relay up to cortex. Georg von Békésy measured these waves, many in human cadaver cochleas, and received the 1961 Nobel Prize. His peaks were far broader than a living ear’s tuning.

The difference is an amplifier. One row of inner hair cells supplies most of the auditory nerve’s afferent fibres. Three rows of outer hair cells receive few afferents but change length when their voltage changes, electromotility, reported in isolated guinea-pig outer hair cells by Brownell and colleagues (1985). The motor is the membrane protein prestin, driven by voltage, not by ATP. On each cycle of a sound the outer hair cells push on the membrane in step, adding energy at the peak, which sharpens tuning and raises sensitivity.

Greenwood’s function (1990) gives the frequency that peaks at each place in the human cochlea:

f = 165.4 × (10^(2.1x) − 0.88), with f in Hz and x the fraction of length measured from the apex

Worked problem: placing two tones. Where do 1,000 Hz and 4,000 Hz peak? Assume a 35 mm cochlea.

Step 1: rearrange. x = log10(f / 165.4 + 0.88) / 2.1.

Step 2: 1,000 Hz. 1000 / 165.4 = 6.046; plus 0.88 is 6.926; log10 is 0.840; divided by 2.1, x = 0.400. That is 0.400 x 35 mm = 14.0 mm from the apex, 21.0 mm from the base.

Step 3: 4,000 Hz. 4000 / 165.4 = 24.18; plus 0.88 is 25.06; log10 is 1.399; divided by 2.1, x = 0.666. That is 23.3 mm from the apex, 11.7 mm from the base.

Step 4: compare. Two octaves span 23.3 − 14.0 = 9.3 mm, and the higher tone sits nearer the base.

Placing a tone on the cochlea⚙ original · interactive

In this sketch the sliders are logarithmic in frequency, about 20 Hz to 20 kHz, the span of the Greenwood function as used here.

A

B

Higher tone
Distance apart on the membrane
Frequency ratio
One octave up from A, from B (mm)

In this sketch: the human Greenwood map, a 35 mm cochlea, peak place only; envelopes are not to scale. The rule to keep: x is measured from the apex, so the distance from the base is 35 mm minus the distance from the apex, and the higher tone peaks nearer the base.

Two ears, two cues

The auditory nerve ends in the cochlear nucleus on the same side (ipsilateral; the other side is contralateral). Above that, the pathway is bilateral. Cochlear-nucleus neurons project to the superior olivary complex on both sides; fibres ascend to the inferior colliculus in the midbrain, which supplies most of the input to the medial geniculate nucleus of the thalamus, which relays to auditory cortex in the temporal lobe (the map of the nervous system places these levels). So deafness in one ear points to the ear, the auditory nerve or the cochlear nucleus: a lesion higher up leaves each ear represented on both sides.

The two sides meet to locate sounds. An interaural time difference (ITD) is the difference in arrival time between the ears. An interaural level difference (ILD) is the difference in loudness, made because the head casts a sound shadow.

Worked problem: how large is an ITD? Treat the ears as two points 0.20 m apart, take sound speed as 343 m/s, and put a distant source at angle theta from straight ahead. The extra path to the far ear is d x sin(theta), so

ITD = d x sin(theta) / c

At 30 degrees: 0.20 m x 0.5 / 343 m/s = 0.000292 s, or 292 microseconds.

At 90 degrees: 0.20 m x 1.0 / 343 m/s = 583 microseconds.

The model ignores the path around the head, so it underestimates real ITDs; the point is the scale.

Neurons in the medial superior olive (MSO) are excited by both cochlear nuclei and fire most when the two inputs arrive together. They handle ITDs, mainly at low frequencies, where spikes can lock to the phase of the wave, firing at the same point in each cycle. Jeffress (1948) proposed that axons of graded length act as delay lines, so each coincidence detector is tuned to one ITD. Bird brainstem circuits, such as the barn owl’s, are commonly cited as fitting that scheme; in the guinea pig, McAlpine, Jiang and Palmer (2001) recorded inferior-colliculus neurons and argued for a population code compared across the two hemispheres.

Neurons in the lateral superior olive (LSO) are excited by the ear on their own side and inhibited, through a relay in the trapezoid body, by the other ear, so their rate reports which ear is louder. They handle ILDs, mainly at high frequencies, where the head shadow is large. Time at low frequencies and level at high frequencies is a tendency, not a wall.

Neither cue tells above from below. The folds of the pinna filter sound differently by elevation, and the brain learns those spectral cues: when Hofman and colleagues (1998) reshaped adults’ pinnae with moulds, elevation judgments were poor at first and then progressively recovered with the moulds in place.

Canals, otoliths and the VOR

Vestibular hair cells use the same transduction with different mechanics. Each semicircular canal is a fluid-filled ring whose swelling, the ampulla, holds hair bundles in a gelatinous flap, the cupula. When the head rotates, endolymph lags by inertia, bends the cupula and deflects the bundles, so canals report rotation. Canals on opposite sides pair in one plane, and a turn excites one partner while inhibiting the other.

The otolith organs sense linear acceleration and gravity. In the utricle, roughly horizontal when you stand, and the saccule, roughly vertical, the bundles are capped by a membrane loaded with calcium carbonate crystals. Tilting or accelerating the head shears that heavier membrane across the hair cells, and the two can give the same shear, so otolith afferents alone are ambiguous. In rhesus monkeys, Angelaki and colleagues (1999) found that after canal inactivation, eye responses to translation followed the ambiguous otolith signal, supporting the view that the brain combines canal and otolith signals to tell tilt from translation.

The canals’ main job is the vestibulo-ocular reflex (VOR), which keeps the eyes still in the world while the head moves. For a head turn to the left:

  1. The left horizontal canal is excited; the right is inhibited.
  2. The left vestibular nucleus excites the right abducens nucleus, whose motor neurons drive the right lateral rectus and turn the right eye rightward.
  3. Abducens interneurons cross and run up the medial longitudinal fasciculus (MLF) to the left oculomotor nucleus, which drives the left medial rectus and turns the left eye rightward.

Both eyes move right as the head turns left. The reflex’s gain is eye velocity divided by head velocity. In a made-up case, a head turning at 100 degrees per second with eyes counter-rotating at 80 degrees per second gives a gain of 0.80, and the image slips across the retina at 20 degrees per second. The cerebellum corrects a wrong gain. Damage to one labyrinth (the vestibular organs of one inner ear) unbalances the pair: the healthy side’s resting firing is no longer matched, and the brain reads the imbalance as rotation, one mechanism of vertigo.

Design problem

Mice lacking prestin lose sensitivity and sharp cochlear tuning. A reviewer says this does not show that outer-hair-cell electromotility is the cochlear amplifier. Why is the reviewer right, and what experiment answers the objection?

One way to do it

Deleting a protein removes everything it does. Knockout outer hair cells had reduced stiffness, and a floppier, shorter or dying cell would also weaken amplification. So the knockout shows prestin is needed, not that its motor action is.

Remove the motor and keep the rest. Dallos and colleagues (2008) made knock-in mice whose prestin carried two substitutions, V499G and Y501H, leaving little electromotility, and checked that outer-hair-cell mechanics and mechanoelectric transduction were preserved. Those mice still lost cochlear amplification, supporting a requirement for prestin-based motility.

Controls to ask for: outer-hair-cell transduction currents; counts of surviving hair cells at the ages tested; thresholds across frequencies, not one tone. Limits: this is the mouse, and the result does not exclude an additional active process in the hair bundle.

How we measure it

Intracellular recording with controlled bundle deflection

An electrode inside a hair cell records its voltage while a probe moves the hair bundle by a known distance and direction. Plotting voltage against displacement gives the cell's input-output curve and its direction sensitivity.

Heterologous expression with nonlinear-capacitance measurement

A candidate gene is expressed in a cell that normally lacks it, here prestin in cultured kidney cells, and the cell is tested for voltage-driven shape change and voltage-dependent charge movement. It shows what the protein can do alone, not whether the ear needs it.

Knock-in mutation with mechanical and transduction controls

An engineered point mutation impairs one function of a protein while the experimenter checks that other properties, such as stiffness and transduction currents, are preserved. It is the step that turns a knockout's correlation into a test of necessity.

Eye-movement recording with canal inactivation

Eye movements are measured in a monkey on a motion platform during tilts and translations, before and after the semicircular canals are inactivated. Comparing the two shows how much the brain relies on canal signals to interpret the otoliths.

Finish line

Test yourself

8 questions

Practice and MCAT-style, with explained answers.

Next · Lesson 13

Touch and Pain

Capsaicin carries no heat, yet it opens the same channel that heat above about 43 °C opens. What is the skin actually measuring?

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