Genetics and Molecular Biology · Unit 4: From gene to protein, and its control
Transcription: From DNA to RNA
Transcription copies one strand of a gene into RNA. This lesson follows the reaction in E. coli, where one core polymerase and a sigma factor find promoters, and in the eukaryotic nucleus, where three polymerases share the work and Pol II needs a set of general transcription factors. You will be able to say how each system starts and stops, and to read a DNA sequence and name the template strand, the coding strand, the direction of travel and the RNA made.
Watch first Which Strand Does the Polymerase Read · 3:05
The death cap mushroom makes a toxin, alpha-amanitin, that blocks one enzyme in your cells at very low doses: RNA polymerase II, which copies genes into messenger RNA. Two other RNA polymerases in the same nucleus work on at the same dose.
Why would a nucleus need three enzymes to do one job? And why can a bacterium such as E. coli manage with one? Both questions are about transcription, the copying of a stretch of DNA into RNA. To answer them you need the reaction itself, then the two systems that run it, then a way to read a sequence and say which strand was copied.
The reaction: RNA copies one strand
RNA polymerase opens a short stretch of the double helix and uses one strand as a guide. That strand is the template strand (also called the antisense or noncoding strand). The polymerase lines up ribonucleoside triphosphates (ATP, GTP, CTP, UTP) by base pairing with the template, A opposite T, U opposite A, G opposite C, and joins each to the 3’ hydroxyl of the chain before it, releasing pyrophosphate. Three rules follow.
- The RNA grows 5’ to 3’, as DNA does in DNA replication.
- Because the RNA is antiparallel to the strand it pairs with, the polymerase reads the template 3’ to 5’.
- The RNA has the same sequence as the other strand, the coding strand (nontemplate strand), with U in place of T.
Unlike DNA polymerase, RNA polymerase needs no primer. It can join the first two nucleotides itself. Think of the coding strand as the printed page and the template as its photographic negative: the polymerase reads the negative and prints a copy of the page.
Where to start is set by a promoter, a DNA sequence where the polymerase and its helpers bind. The first nucleotide copied into RNA is called +1. Bases toward the 5’ end of the coding strand are upstream and get negative numbers; bases past +1 are downstream. Where to stop is set by a terminator. Each gene uses only one strand as template, but neighboring genes can use opposite strands.
Bacteria: one core enzyme and a sigma factor
In E. coli one kind of core enzyme makes nearly all cellular RNA. It has five subunits: two alpha, one beta, one beta’ (beta prime) and one omega. Core can copy DNA, but it does not find promoters well. A sigma factor binds the core to form the holoenzyme, and sigma reads the promoter.
The housekeeping sigma of E. coli, sigma 70, recognizes two short elements on the coding strand. Their consensus, the most common base at each position across many promoters, is:
-35 element: 5’-TTGACA-3’ … about 17 bp … -10 element: 5’-TATAAT-3’
The -10 element is also called the Pribnow box, after David Pribnow, who in 1975 reported the sequence of a polymerase binding site at an early promoter of phage T7. Real promoters differ from consensus at several positions. A closer match usually means more initiation, but not always, since other DNA and other proteins also matter.
Initiation goes in steps. The holoenzyme binds double-stranded DNA (the closed complex), then melts about a turn of the helix around the -10 element and the start site to form the open complex, with the template strand placed in the active site. The enzyme then makes and releases many short RNAs while still sitting at the promoter, a stage called abortive initiation. Eventually one RNA grows long enough, and the polymerase leaves the promoter (promoter escape) and elongates. Textbooks often say sigma is released at escape. In single-molecule work with purified E. coli enzyme, a substantial share of elongating complexes kept sigma 70, so release is better called common than obligatory.
Other sigmas send the same core to other genes. In E. coli, sigma 32 directs it to heat-shock genes, so a temperature rise changes which promoters are used.
Because bacteria have no nucleus, ribosomes can start translating an mRNA while its 3’ end is still being made. Many bacterial mRNAs are polycistronic, carrying the coding sequences of several genes from one promoter (an operon, the subject of the lac operon), but not all are.
Eukaryotes: three polymerases and the general factors
The nucleus divides the work among three polymerases. In mammalian cells:
- Pol I makes the large rRNA precursor (45S or 47S), later cut into 28S, 18S and 5.8S rRNA.
- Pol II makes the precursors of mRNAs, most small nuclear RNAs (snRNAs) and the precursors of microRNAs.
- Pol III makes tRNAs, 5S rRNA, U6 snRNA and other small RNAs.
Their sensitivity to alpha-amanitin differs, which is why the toxin in the opening blocks only some RNAs.
Pol II cannot find a promoter by itself. It needs the general transcription factors, named TFII plus a letter, which assemble with it at the core promoter into a preinitiation complex:
- TFIID contains the TATA-binding protein (TBP) and other subunits, and binds the core promoter first.
- TFIIA and TFIIB steady TBP on the DNA; TFIIB also helps set the start site and bridges to Pol II.
- TFIIF arrives with Pol II; TFIIE then recruits TFIIH.
- TFIIH has a translocase subunit (XPB) that helps open the DNA, and a kinase subunit (CDK7).
A TATA box (consensus TATAAA) sits about 25 to 30 bp upstream of the start site in promoters that have one. Most human promoters do not. At those, TFIID is placed through other core elements, such as the initiator that covers the start site.
The largest Pol II subunit ends in a tail called the CTD (carboxy-terminal domain), made of repeats of seven amino acids, YSPTSPS. Human Pol II has 52 repeats and budding yeast 26. As the polymerase starts, CDK7 phosphorylates serine 5 of the repeats, and during elongation serine 2 is phosphorylated by other kinases. The phosphorylated tail acts as a landing pad: it recruits the enzymes that cap the RNA and later those that splice it and cut its 3’ end (see RNA processing). Proteins that switch genes on, such as the ones at the ends of signaling pathways to the nucleus and the nuclear receptors, act largely by helping or hindering this assembly. They bind DNA with the kind of specific, regulated contacts described in protein binding and allostery.
Once it escapes, Pol II can travel fast. In one study of long genes in cultured human cells, the average rate was about 3.8 kb per minute. If a gene ran 114 kb at that constant rate, ignoring pauses:
time = length / rate = 114 kb / 3.8 kb per min = 30 min
That is elongation alone, not the time to a finished mRNA. Rates differ among genes and cell types.
Stopping: termination in each system
E. coli uses two kinds of terminator, and they overlap.
An intrinsic terminator is written into the RNA itself: a GC-rich stretch that folds back into a hairpin, followed by a run of U residues. The hairpin forms in the RNA exit channel while the U tract holds the RNA to the template by weak A-U pairs, and together they release the RNA. A Rho-dependent terminator needs Rho, an ATP-driven protein that binds the nascent RNA at a Rho utilization (rut) site, moves along the RNA toward the polymerase, and pulls it off. The two classes are less separate than the textbook split suggests: in an atlas of Bacillus subtilis terminators, Rho stimulated about 10% of the intrinsic ones.
In eukaryotes each polymerase stops its own way. For Pol II, termination is coupled to processing. After the polymerase copies the poly(A) signal, the enzyme CPSF73 cuts the RNA, and the RNA still attached to the polymerase is chewed 5’ to 3’ by XRN2. In the torpedo model XRN2 catches the polymerase and knocks it off. In the allosteric model the polymerase changes after the signal and slows. In cultured human cells, experiments that rapidly removed these factors support a combination: slowing beyond the poly(A) site lets XRN2 catch up. Pol III stops at a run of T residues in the nontemplate strand, though in budding yeast the run is not always sufficient and RNA structure and the helicase Sen1 assist.
Strands and directions: the sequence problem
top: 5'-TACGGATCCATGAAACGT-3'
bottom: 3'-ATGCCTAGGTACTTTGCA-5'
RNA: 5'-ACGUUUCAUGG-3' (made from this region)
Step 1. Check the duplex. Pair each base: T with A, A with T, C with G and so on across all 18 positions. Every pair matches, so the two strands are complementary.
Step 2. Write each strand 5’ to 3’. The top already is: TACGGATCCATGAAACGT. Reverse the bottom: 5’-ACGTTTCATGGATCCGTA-3’.
Step 3. Find the strand that matches the RNA, with T for U. The RNA, ACGUUUCAUGG, matches the first 11 bases of the bottom strand read 5’ to 3’ (ACGTTTCATGG). It does not occur in the top strand. So the bottom strand is the coding strand.
Step 4. The template is the other strand. The top strand is the template. Check: the RNA pairs with the top strand antiparallel. RNA 5’-A pairs with the top strand’s 3’-T, RNA C with G, G with C, and so on leftward.
Step 5. Direction of travel. The polymerase reads the template 3’ to 5’. On the top strand, 3’ is at the right, so the polymerase moves right to left along the page. The RNA grows 5’ to 3’ in that same leftward direction, and its 5’ end lies toward the right of the duplex as written.
Two checks catch most mistakes. The RNA must be antiparallel to its template. And without the RNA or a promoter, a bare duplex does not tell you which strand is the template.
Rule to keep: a bare duplex does not tell you the template; the promoter, or the RNA, does. The polymerase reads the template 3′ to 5′, builds RNA 5′ to 3′, and the RNA matches the coding strand with U for T. The picture shows only the stretch drawn and is a sketch of the logic; the lesson does not draw a promoter, so its placement beside +1 here is not to scale.
Design problem
A newly found mammalian gene makes an RNA of unknown type. Design an experiment to decide which nuclear RNA polymerase transcribes it.
One way to do it
Use the different sensitivities of the three polymerases to alpha-amanitin. Isolate nuclei from the cells and run a nuclear run-on: give the nuclei labeled nucleotides so that polymerases already on genes extend their RNAs. Set up a series of alpha-amanitin concentrations spanning several orders of magnitude, from none through roughly 1 µg/mL to a few hundred µg/mL. (These values are orders of magnitude for mammalian cells and should be checked against your cell type.) Measure labeled RNA from the new gene and from three controls: an rRNA gene (Pol I), a protein-coding gene such as actin (Pol II), and a tRNA or 5S rRNA gene (Pol III).
In mammalian cells you expect the Pol II control to drop at low doses, around 1 µg/mL or less; the Pol III control to drop only at roughly 100 to 1000 times more; and the Pol I control to resist across the range. Match the new gene’s curve to one control. The same titration can be done by in vitro transcription in a nuclear extract with the gene as template.
Then confirm. Map the RNA’s 5’ end by primer extension or from RNA-seq data to locate the start site, and inspect the region upstream for promoter elements of the matching class. Finally, fuse that promoter region to a reporter gene and test whether its expression shows the same alpha-amanitin sensitivity.
How we measure it
In vitro transcription with purified components
You mix a DNA template, purified polymerase, chosen factors and labeled nucleotides, then measure the RNA made. Adding or removing one component tells you what it is needed for, as when sigma restored transcription of phage DNA or general factors let Pol II start at a promoter.
Column chromatography of enzyme activity
A cell extract is passed through a resin that holds proteins by charge, and fractions are collected and assayed. Separate peaks of activity show separate enzymes or separable parts, which is how sigma was split from core and how Pol I, II and III were first resolved.
Nuclear run-on assay
Nuclei are isolated and given labeled nucleotides, so polymerases already engaged on genes extend their RNAs a short distance. Measuring labeled RNA from a given gene reports how much it was being transcribed, and adding inhibitors such as alpha-amanitin shows which polymerase does it.
X-ray crystallography and cryo-EM
Crystals or frozen particles of a polymerase complex are imaged to build an atomic model. The models show where the template, the RNA and each factor sit, which turns a list of steps into a physical mechanism.
Finish line
Test yourself
8 questions
Practice and MCAT-style, with explained answers.
Next · Lesson 17
RNA Processing: Caps, Tails and Splicing
Why is a message copied from more than 5,000 nucleotides of DNA only 737 nucleotides long?
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