Cell Signaling · Unit 1: How a cell knows anything
Binding: Affinity, Occupancy and Dose–Response
A drug or hormone acts by occupying a receptor, and how much it occupies follows one equation. This lesson shows how to read affinity, potency and efficacy from binding and dose-response curves, and why a tissue can respond fully while most of its receptors are empty. You will finish able to calculate occupancy from Kd and to identify a blocker from the way it moves a curve.
Watch first A Full Response, Mostly Empty Receptors · 2:47
Naloxone can pull a person out of a morphine overdose within minutes, and it never reacts with a single molecule of morphine. The two drugs compete for the same place on the same cells. This lesson asks how much of that place a given dose fills, and how filling it becomes a response.
The idea: a drug acts at a site it has to occupy
In 1905 John Langley, in Cambridge, tested two drugs on skeletal muscle. Nicotine made the muscle contract and curare prevented it, and both still worked after the nerve to the muscle had been cut and had degenerated. So the drugs were acting on the muscle itself. Langley called the thing they acted on the receptive substance. A few years earlier Paul Ehrlich, working on how the body makes antitoxins, had coined a shorter word for a related idea about toxins and nutrients, not yet about drugs: receptor.
The picture that still works is Emil Fischer’s lock and key. An agonist is a molecule that binds a receptor and switches it on: the key fits and turns. An antagonist binds the same receptor and does nothing there: the key fits, will not turn, and keeps the other key out.
One equation: occupancy follows mass action
Picture a room with a fixed number of coat hooks. Coats go in, catch on hooks and drop off again. The hooks are receptors (R). The coats are ligand (L), meaning any molecule that binds the receptor. The fraction of hooks holding a coat is the fractional occupancy.
The real mechanism is a reversible reaction, L + R ⇌ LR. At equilibrium, binding and release happen at the same rate, and the balance point is the dissociation constant: Kd = [L] × [R] / [LR]. Solve for the fraction of receptors bound and you get this lesson’s one equation:
fractional occupancy = [L] / (Kd + [L])
Set [L] equal to Kd and the answer is one half. So Kd is the concentration of ligand that fills half of the receptors. It measures affinity: a small Kd means a tight grip, because very little ligand is needed to half-fill the sites.
This is the Michaelis–Menten equation from the enzyme kinetics lesson, with occupancy in place of v/Vmax and Kd in place of Km. Both are hyperbolas for the same reason: a fixed number of sites is being filled. One caution: Km combines several rate constants, while Kd is a pure binding constant. In 1926 Alfred Clark fitted this same hyperbola, which A. V. Hill had used for nicotine in 1909 and Irving Langmuir for gas sticking to a surface, to the response of frog heart muscle to acetylcholine.
At [L] = Kd/9, occupancy is 10%. At [L] = 9 × Kd, it is 90%. Getting from 10% to 90% takes an 81-fold increase in ligand, nearly two powers of ten. That is why these curves are drawn with concentration on a logarithmic axis. On a linear axis the low-dose end is crushed against the origin. On a log axis the hyperbola becomes a symmetric S-shaped curve with Kd at its midpoint. Try it in the explorer below.
- Apparent EC₅₀ (relative units)
- 1.0
- Ceiling response
- 100%
The dose that gives half-maximal response is the EC₅₀ — the lower it is, the more potent the drug. Efficacy is how high the curve can reach.
Potency (EC₅₀, the curve's horizontal position) and efficacy (Emax, its height) are independent. A competitive antagonist slides the curve right but can be overcome with more agonist; it never lowers the ceiling.
A climb from 10% to 90% in much less than 81-fold means the sites are not acting independently. That is cooperativity, which belongs to the lesson on protein binding and allostery.
Potency is not efficacy, and response is not occupancy
Occupancy counts the receptors that have ligand bound. Response is what the tissue does: a muscle shortens, a gland secretes. A dose–response curve plots the second, and it has two numbers of its own.
EC50 is the concentration that gives half of the drug’s maximum response. It measures potency: the lower the EC50, the less drug you need. Emax is the largest response the drug can produce, however much you add. It reflects efficacy: how well the drug switches the receptor on once it is bound.
These are separate properties. A full agonist can drive the tissue to its maximum. A partial agonist levels off below that maximum even when it occupies every receptor, like a key that turns the lock only part of the way. Buprenorphine is a partial agonist at the receptor that morphine activates and naloxone blocks.
Compare three drugs acting at one receptor in one tissue. The first has an EC50 of 1 nM and reaches 100%. The second has an EC50 of 100 nM and also reaches 100%: 100-fold less potent, with the same maximum. The third has an EC50 of 1 nM but tops out at 40%: as potent as the first, less efficacious.
Add a partial agonist to a tissue that is already responding fully to a full agonist, and the response falls. Each receptor the weak key takes is one the strong key has lost. In that setting the partial agonist behaves as an antagonist.
The response saturates before the receptors do
Clark assumed that response is proportional to occupancy, which would make EC50 equal to Kd. In 1956 Mark Nickerson published a short paper in Nature called “Receptor occupancy and tissue response.” He reported that a tissue can reach its full response before all of its receptors are occupied.
The reason is amplification in the pathway after the receptor. Picture a bottling line where the capper is the bottleneck: once it runs at full speed, extra filling machines add nothing. Likewise, once enough receptors are occupied to saturate the slowest step downstream, more occupied receptors change nothing you can measure. The receptors that are not needed are called spare receptors, and together they make up the receptor reserve. They are ordinary receptors. The tissue has more copies than the pathway can use at once.
Kd is a property of the receptor. EC50 is a property of the whole pathway. With a reserve, EC50 sits below Kd.
How far below? Say the pathway reaches its ceiling at 5% occupancy and responds in proportion below that. Half the maximum then needs 2.5% occupancy. Solving [L] / (Kd + [L]) = 0.025 gives [L] = Kd/39, so the EC50 is 39-fold below the Kd with no change in binding.
Treating an EC50 as a binding affinity is a common error in the research literature. You can also use the gap as a tool. If a treatment changes a drug’s EC50 and leaves its Kd alone, something after binding has changed, and you can look for it.
Design problem
A drug gives a full response when only about 5% of its receptors are occupied. State what that tells you, then design an experiment that would prove it.
One way to do it
What it tells you: for this drug in this tissue, about 95% of the receptors are spare. A step after the receptor saturates first, so the EC50 lies well below the Kd. The reserve belongs to the pair of drug and tissue. A weaker agonist on the same tissue might need every receptor.
The experiment: take receptors away and watch the curve. Use an irreversible antagonist, a blocker that bonds covalently to the receptor and cannot be washed off or outcompeted. Treat strips of tissue so that different fractions of the receptors are destroyed, wash, then run a full agonist dose–response curve on each strip. In matched samples, count with a radioactive ligand what fraction of the receptors each treatment removed.
The predictions, taking the 5% figure at face value:
- Half of the receptors gone. The drug must now occupy 10% of the survivors. You still get a full response at a higher dose, so the curve moves right.
- 90% gone. The drug must occupy half of the survivors. Still a full response, further right.
- More than 95% gone. Even with every survivor occupied, the tissue is short of the number it needs. Now the maximum falls.
A rightward shift first and a lower maximum afterwards is the proof. With no reserve, the maximum would start to fall with the first receptors lost. Real tissues have no sharp threshold, so the maximum sags gradually near the limit, but the order of events is the same.
As a control, a second agonist acting through a different receptor should keep its full maximum, which shows that the blocker left the downstream pathway undamaged.
Blocking the receptor: the shape of the shift names the blocker
Go back to the coat hooks and throw in decoy coats that take up hooks and produce no response.
A competitive antagonist binds reversibly at the agonist’s own site. Add enough agonist and it wins the hooks back, so the maximum is unchanged. What changes is the dose you need. On a log axis the whole curve slides to the right, parallel to itself. This is what naloxone does to morphine.
The size of the slide is the dose ratio: how many times more agonist you need for the same response.
dose ratio = 1 + [B] / KB
[B] is the antagonist concentration and KB is the antagonist’s own dissociation constant. J. H. Gaddum wrote down the competition equation in 1937. In 1947 Heinz Schild turned it into a measurement he called pA2: the negative logarithm of the antagonist concentration that forces you to double the agonist dose. At a dose ratio of 2, [B] equals KB. Two ordinary dose–response curves therefore give the affinity of a blocker for a site that nobody has isolated.
A non-competitive antagonist takes receptors out of play in a way that more agonist cannot reverse. It may bind somewhere else on the receptor, or bind at the agonist’s site and never let go. Its signature is a lower maximum. In a tissue with a receptor reserve, as the design problem showed, the first receptors lost cost only a rightward shift.
Potency rankings also sort receptors into types. In 1948 Raymond Ahlquist ranked six adrenaline-like drugs by potency on many tissues. Blood delivers adrenaline to every organ at much the same concentration, yet it narrows arteries and relaxes airways. In arteries adrenaline and noradrenaline ranked high and isoproterenol low. In airways and heart the ranking ran nearly the other way. No third order appeared. One kind of pocket predicts one order everywhere, so he proposed two kinds and named them alpha and beta.
The proof: binding you can count
Every argument so far infers the receptor from a response. In 1973 Candace Pert and Solomon Snyder at Johns Hopkins measured binding itself, as did two other groups the same year. They mixed radioactive naloxone with ground-up brain tissue, pulled the mixture through a filter, washed the filter and counted the radioactivity that stayed behind.
Brain is greasy and will hold on to almost any small molecule. So how do you show that what stuck is a receptor?
The binding has to be saturable. A finite set of sites fills up along the occupancy curve, while sticking to grease keeps rising with concentration. It has to be specific: unlabelled opiates pushed the radioactive naloxone off in the order of their known potency as drugs. And it has to be stereospecific. Levorphanol, an active opiate, displaced the label. Dextrorphan, its mirror image, has almost no opiate action and was far weaker. Grease cannot tell a molecule from its mirror image. A shaped pocket can.
The saturation curve hands you the numbers in this lesson’s equation, now measured on the site itself: a Kd, and the total count of sites, called Bmax. Langley’s receptive substance had become something you could count.
How we measure it
Isolated-tissue bioassay (organ bath)
A strip of muscle or a piece of heart is kept alive in warm, oxygenated salt solution and connected to a recorder. You add a drug at rising concentrations and measure the contraction or relaxation at each one. The result is a dose-response curve, from which EC50 and Emax are read.
Radioligand binding assay
Membranes are incubated with a radioactive ligand, then filtered and washed, and the radioactivity left on the filter is counted. Repeating the incubation with a large excess of unlabelled ligand measures nonspecific sticking, which is subtracted. The specific binding that remains saturates, and its curve gives Kd and the number of sites (Bmax).
Schild analysis
You measure agonist dose-response curves at several concentrations of an antagonist and calculate the dose ratio for each. For a competitive antagonist, log(dose ratio − 1) plotted against log antagonist concentration is a straight line of slope 1. The point where the line crosses zero gives KB, the antagonist's dissociation constant.
Irreversible receptor inactivation
A tissue is treated with a blocker that bonds covalently to the receptor and is then washed, so that a fraction of the receptors is permanently removed. Comparing agonist curves before and after shows whether the curve moves right before its maximum falls. That order reveals a receptor reserve.
Finish line
Test yourself
8 questions
Practice and MCAT-style, with explained answers.
Next · Lesson 4
A Field Guide to Receptors
Acetylcholine starts a muscle twitch and slows a heart. Same molecule: what decides what it means?
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